A surgical technique is performed on 10 patients. You are told there is an 80% chance of success. Find the probability that the surgery is successful for exactly 6 patients.

Respuesta :

Answer:

0.0881

Step-by-step explanation:

This is binomial distribution probability that can be solve using the formula:

[tex]P(x)=\frac{n!}{(n-x)!x!}p^{x}q^{n-x}[/tex]

Where n is total number of trials [here it is 10]

x is what we want to find [here, we want for 6 patients, so x = 6]

p is probability of success [p = 0.8]

q is probability of failure [ 1 - p = q = 0.2]

Substituting, we get:

[tex]P(x)=\frac{n!}{(n-x)!x!}p^{x}q^{n-x}\\P(x=6)=\frac{10!}{(10-6)!6!}(0.8)^{6}(0.2)^{5}\\P(x=6)=0.0881[/tex]