Answer:
The actual yield of iron is 0.208 moles.
Explanation:
Given data:
Moles of Fe₂O₃ = 0.301 mol
Mass of iron = 11.6 g
Actual yield of iron in moles = ?
Solution:
Number of moles = mass / molar mass
Number of moles = 11.6 g/ 55.85 g/mol
Number of moles = 0.208 mol
It is the actual yield of iron in moles.
Theoretical yield can be calculated from given data.
One mole of Fe₂O₃ produce two mole two mole of iron.
0.301 moles will produce:
0.301× 2 = 0.602 mol
Theoretical yield in moles will be 0.602 moles.
