Answer:
0.4 s
Explanation:
The time that the ball is in the air can be found with the next formula:
[tex]time = t = \frac{2v_{o}sen\beta}{g}[/tex]
where [tex]v_{o}[/tex] is the initial velocity of the ball, in this case:
[tex]v_{o}=4.00 m/s[/tex]
β is the angle: β = 29.0°
And g is the acceleration of gravity: [tex]g=9.81m/s^2[/tex]
Replacing all the values to find t, we have:
[tex]time = t = \frac{2(4m/s)sen(29)}{9.81m/s^2} = 0.4s[/tex]
Thus, the ball is 0.4s in the air.
