Respuesta :
Answer:
35Cl ⇒ 34.968853 amu has an abundance of 30.05%
Explanation:
The molar mass of chlorine, (which is the average of all its naturally stable isotope masses), is 36.36575 amu.
There are 2 naturally stable isotopes, this means together they have an abundance of 100%
The isotopes are:
35Cl ⇒ 34.968853 amu has an abundance of X %
37Cl ⇒ 36.965903 amu has an abundance of Y %
X + Y = 100% OR X = 100% - Y
36.36575 = 34.968853X + 36.965903Y
36.36575 = 34.968853(1-Y) + 36.936.96590365903Y
36.36575 = 34.968853 -34.968853Y + 36.965903Y
1.396897 = 1.99705Y
Y = 0.699 = 69.95%
X = 100-69.9 = 30.05%
To control, we can plug in the following equation:
34.968853 * 0.3005 + 36.965903 * 0.6995 = 36.3658
This means
37Cl ⇒ 36.965903 amu has an abundance of 69.95 %
35Cl ⇒ 34.968853 amu has an abundance of 30.05%
Considering the definition of atomic mass, isotopes and atomic mass of an element, the relative percent abundance of 35Cl is 30.05%.
Definition of atomic mass
First of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.
Definition of isotope
The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.
Definition of atomic mass
On the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.
Relative percent abundance of 35Cl
In this case, 35Cl has an atomic mass of 34.968853 amu and a percent natural abundance of x%.
On the other side, 37Cl has an atomic mass of 36.965903 amu and a percent natural abundance of y%.
There are 2 naturally stable isotopes, this means together they have an abundance of 100%. Then y%= 100% - x%
Then, the molar mass for a sample of chlorine 36.36575 g/mol, the average mass of chlorine can be calculated as:
34.968853 amu× x + 36.965903 amu× (1-x)= 36.36575 amu
34.968853 amu× x + 36.965903 amu× 1- 36.965903 amu× x= 36.36575 amu
34.968853 amu× x - 36.965903 amu× x= 36.36575 amu - 36.965903 amu
-1.99705 amu× x= -0.600153 amu
x= (-0.600153 amu)÷ (-1.99705 amu)
x=0.3005 =30.05%
Finally, the relative percent abundance of 35Cl is 30.05%.
Learn more about average atomic mass:
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