Two objects move with initial velocity 28.00 m/s, final velocity 16.0 m/s, and constant accelerations. (a) The first object has displacement 20.0 m. Find its acceleration. (b) The second object travels a total distance of 22.0 m. Find its acceleration.

Respuesta :

Explanation:

It is given that,

Initial velocity of both objects, u = 28 m/s

Final velocity of both objects, v = 16 m/s

(a) Displacement of first object, d₁ = 20 m. Let a is the acceleration of object 1. Using third equation of kinematics as :

[tex]a=\dfrac{v^2-u^2}{2d_1}[/tex]

[tex]a=\dfrac{(16)^2-(28)^2}{2\times 20}[/tex]

[tex]a=-13.2\ m/s^2[/tex]

(b) Displacement of first object, d₂ = 22 m. Let a is the acceleration of object 1. Using third equation of kinematics as :

[tex]a=\dfrac{v^2-u^2}{2d_2}[/tex]

[tex]a=\dfrac{(16)^2-(28)^2}{2\times 22}[/tex]

[tex]a=-12\ m/s^2[/tex]

Hence, this is the required solution.

To find the velocity or acceleration of a object , we use three equations of motion.

  • a) The acceleration of the first object is [tex]-13.2\rm m/s^2[/tex].
  • b) The acceleration of the second object is [tex]-12\rm m/s^2[/tex].

What are the equations of motion?

To find the velocity or acceleration of a object , we use three equations of motion as,

[tex]v=u+at\\s=ut+\dfrac{1}{2}at^2\\v^2=u^2+2as[/tex]

Here, [tex]u[/tex] velocity, [tex]a[/tex] acceleration, [tex]v[/tex] is the velocity, [tex]t[/tex] time, and [tex]s[/tex]distance traveled.

Given information-

Two objects move with initial velocity 28.00 m/s.

Two objects move with final velocity 16.00 m/s.

  • (a) The first object has displacement 20.0 m. The acceleration of it-

By the third equation of motion, we can find the acceleration as,

[tex]a=\dfrac{v^2-u^2}{2s}[/tex]

Put the values as,

[tex]a=\dfrac{16^2-28^2}{2\times20_1}\\a=-13.2\rm m/s^2[/tex]

Thus the acceleration of the first object is [tex]-13.2\rm m/s^2[/tex].

  • (b) The second object travels a total distance of 22.0 m. Find its acceleration.

As the distance is 22 for the second object thus its acceleration is,

[tex]a=\dfrac{16^2-28^2}{2\times22_1}\\a=-12\rm m/s^2[/tex]

Thus the acceleration of the second object is [tex]-12\rm m/s^2[/tex].

Learn more about the equation of the motion here;

https://brainly.com/question/8898885

Hence,

  • a) The acceleration of the first object is [tex]-13.2\rm m/s^2[/tex].
  • b) The acceleration of the second object is [tex]-12\rm m/s^2[/tex].