Consider the hypothetical reaction 3A + 4B → C + 2D Over an interval of 2.50 s the average rate of change of the concentration of A was measured to be -0.0560 M/s. What is the final concentration of B at the end of this same interval if its concentration was initially 1.700 M?

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Answer:

Final [B] = 1.665 M

Explanation:

3A + 4B → C + 2D

Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt

0.05600 M/s = 4 [B]/ 2.50 s

[B] = 0.035 M (concentration of B consumed)

Final [B] = initial [B] - consumed [B]

Final [B] = 1.700 M - 0.035 M

Final [B] = 1.665 M

The final concentration of B in the reaction is 1.735 M.

The rate of the reaction is the change in the concentration in the given time. The equation for the reaction is given as:
[tex]\rm 3\;A\;+4\;B\to\;C\;+\;2\;D[/tex]

Computation for the final concentration of B

The rate of B with respect to A has been

[tex]\rm 3\;\dfrac{dA}{dt}=4\;\dfrac{dB}{dt}[/tex]

The rate of change of A is -0.0560 M/s

The change in B is given as:

[tex]\rm 0.0560=4\dfrac{dB}{2.50}\\ dB=0.035\;M[/tex]

The change in concentration of B is 0.035 M.

The final concentration of B is :

[tex]\rm Final \;concentration=Initial \;+concentration-dB\\Final\;concentration=1.700+0.035\\Final\;concentration=1.735\;M[/tex]

The final concentration of B in the reaction is 1.735 M.

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