Answer: 0.48
Step-by-step explanation:
Given : The probability that a customer will order a hamburger P(H)= 0.60.
The probability that a customer will order french fries P(F)= 0.50.
The restaurant has also determined that if a customer orders a hamburger, the probability the customer will also order fries : P(F|H)= 0.80.
Using conditional probability formula , for any event A (first event) and B (second event), we have:-
[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow\ P(A\cap B)=P(A)\timesP(B|A)[/tex]
Similarly, the probability that the order will include a hamburger and fries :-
[tex]P(H\cap F)=P(H)\times P(F|H)\\\\=0.60\times0.80\\\\=0.48[/tex]
Hence, the probability that the order will include a hamburger and fries=0.48
