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a 1500 kg car traveling at 15 m/s to the south collides with a 4500 kg truck that is intially at rest at a spotlight. The car and the truck stick together and move together after the collison. What is the final velocity of the two-vehicle mass​

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MathPhys

Answer:

3.75 m/s south

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

Since the car and truck stick together, v₁ = v₂.

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

Given m₁ = 1500 kg, u₁ = -15 m/s, m₂ = 4500 kg, and u₂ = 0 m/s:

(1500 kg) (-15 m/s) + (4500 kg) (0 m/s) = (1500 kg + 4500 kg) v

-22500 kg m/s = 6000 kg v

v = -3.75 m/s

The final velocity is 3.75 m/s to the south.

nuhulawal20

The final velocity of the two-vehicle mass​ as they moved together after the collision is 3.75m/s

Given the data in the question;

  • Mass of the car; [tex]m_1 = 1500kg[/tex]
  • Velocity of the car; [tex]v_1 = 15m/s[/tex]
  • Mass of the truck; [tex]m_2 = 4500kg[/tex]
  • Velocity of truck; [tex]v = 0m/s[/tex]

Final or Combined velocity of the two-vehicle mass​; [tex]V_{combined} = \ ?[/tex]

To determine final or combined velocity of the two-vehicle mass, we use Conservation of Momentum:

[tex]m_1v_1\ +\ m_2v_2 = ( m_1\ +\ m_2)V_{combined}[/tex]

We substitute our given values into the equation

[tex]( 1500kg\ *\ 15m/s) + ( 4500kg\ *\ 0m/s) = ( 1500kg + 4500kg)V_{combined}\\\\22500kg.m/s + 0 = ( 6000kg)V_{combined}\\\\V_{combined} = \frac{22500kg.m/s}{6000kg}\\\\V_{combined} = 3.75 m/s[/tex]

Therefore, the final velocity of the two-vehicle mass​ as they moved together after the collision is 3.75m/s.

Learn more: https://brainly.com/question/18150585

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