Respuesta :
Explanation:
It is given that,
Voltage to accelerate electrons to hit a copper plate and produce X-rays, [tex]V_1=21\ kV=21\times 10^3\ V[/tex]
Using the conservation of energy for the electrons as :
[tex]21\times 10^3=\dfrac{1}{2}mv^2[/tex]
[tex]v=\sqrt{\dfrac{2V}{m}}[/tex]
m is the mass of electron
[tex]v=\sqrt{\dfrac{2\times 21\times 10^3}{9.1\times 10^{-31}}}[/tex]
[tex]v=2.14\times 10^{17}\ m/s[/tex]
For the proton, mass, [tex]m'=1.67\times 10^{-27}\ kg[/tex]
Now using the conservation of energy for the protons. We get :
[tex]V=E=\dfrac{1}{2}m'v^2[/tex]
[tex]V=\dfrac{1}{2}\times 1.67\times 10^{-27}\times (2.14\times 10^{17})^2[/tex]
[tex]V=3.82\times 10^7\ volts[/tex]
Hence, this is the required solution.
