Answer:2538.43 N
Explanation:
Given
Mass of Log=205 kg
Ramp angle[tex]=25^{\circ}[/tex]
Coefficient of Friction=0.855
log acceleration[tex]=0.647 m/s^2[/tex]
Let T be the Tension
[tex]T-mgsin\theta -f_r=ma[/tex]
Here [tex]f_r=frictional\ Force=\mu N=0.855mgcos\theta =1556.76 N[/tex]
[tex]T=mgsin25+m\times 0.647+1556.76[/tex]
T=849.04+132.63+1556.76=2538.435 N