Answer:
Bottom left corner.
Step-by-step explanation:
in order to solve this, you just have to evaluate the function when x=0 that means the intersect with Y-axis, so when h(x) = x^3 + 2x^2 - 11x - 12 is evaluated for x=0
y=-12
So the point would be (0,-12)
From the graphs there are two graphs that match this description, now we just have to evaluate the intersect with X, in the bottom left it says that when y=0 x=-4
So we evaluate h(x) = x^3 + 2x^2 - 11x - 12 to x=-4 to see if it equals 0:
[tex]h(x) = x^3 + 2x^2 - 11x - 12\\h(x) = -4^3 + 2(-4)^2 - 11(-4) - 12\\h(x) = -64 +32 +44 - 12\\\\h(x)=0[/tex]
As you can see the function equals 0 that means that is the graph of h(x) = x^3 + 2x^2 - 11x - 12
