Answer:
The answer to your question is:
a) 4.64 x 10 ¹⁵ molecules
b) 9.28 x 10 ¹⁵ atoms of O2
Explanation:
MW C7H14O2 = 84 + 14 + 32 = 130 g
a) 130 g of C7H14O2 ---------------- 1 mol of C7H14O2
1 x 10 ⁻⁶ g --------------- x
x = 7.7 x 10 ⁻⁹ mol
1 mol of C7H14O2 -------------- 6 .023 x 10 ²³ molecules
7.7 x 10⁻⁹ mol -------------- x
x = 4.64 x 10¹⁵ molecules
b) 130 g of C7H14O2 ---------------- 1 mol of C7H14O2
1 x 10⁻⁶ C7H14O2 ----------------- x
x = 7.7 x 10 ⁻⁹ mol of C7H14O2
1 mol of C7H14O2 --------------- 2 mol of O2
7.7 x 10 ⁻⁹ ---------------- x
x = 1.54 x 10⁻⁸ mol of O2
1 mol of O2 ----------------- 6.023 x 10 ²³ atoms
1.54 x 10 ⁻⁸ ---------------- x
x = 9.28 x 10 ¹⁵ atoms of O2
1 μg of C₇H₁₄O₂ contains 4.62 × 10¹⁵ molecules and there are 3.23 × 10¹⁶ atoms of carbon present.
First, we want to calculate the number of molecules in 1 μg (1 × 10⁻⁶ g) of C₇H₁₄O₂. We will use the following relationships.
[tex]1 \times 10^{-6}g \times \frac{1mol}{130.18g} \times \frac{6.02 \times 10^{23}molecules }{1mol} = 4.62 \times 10^{15}molecules[/tex]
The molar ratio of C₇H₁₄O₂ to C is 1:7. The number of atoms of C in 4.62 × 10¹⁵ molecules of C₇H₁₄O₂ is:
[tex]4.62 \times 10^{15}molecule \times \frac{7C\ atoms}{1molecule} = 3.23 \times 10^{16} C\ atoms[/tex]
1 μg of C₇H₁₄O₂ contains 4.62 × 10¹⁵ molecules and there are 3.23 × 10¹⁶ atoms of carbon present.
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