Answer:
A. 0.14
B. 0.0048
C. 0.3467
Step-by-step explanation:
You are given the table
[tex]\begin{array}{ccccc}\text{Credit Card}&\text{Visa}&\text{Master}&\text{American Express}&\text{Discover}\\ \\\text{East Coast}&0.45&0.37&0.16&0.02\\\text{Midwest}&0.40&0.43&0.03&?\end{array}[/tex]
The sum in each row must be equal to 1, so
[tex]0.40+0.43+0.03+?=1\\ \\?=1-0.86=0.14[/tex]
Hence, the table is
[tex]\begin{array}{ccccc}\text{Credit Card}&\text{Visa}&\text{Master}&\text{American}&\text{Express}\\ \\\text{East Coast}&0.45&0.37&0.16&0.02\\\text{Midwest}&0.40&0.43&0.03&0.14\end{array}[/tex]
A. The probability that a person from Midwest has Discover card is
[tex]0.14[/tex]
B. The probability that a person chosen at random from East Coast and Midwest, independently of one another, both have type American Express is
[tex]0.16\cdot 0.03=0.0048[/tex]
C. The probability that a person chosen at random from East Coast and Midwest, independently of one another, both have the same type of credit card is
[tex]0.45\cdot 0.40+0.37\cdot 0.43+0.16\cdot 0.03+0.02\cdot 0.14=0.3467[/tex]
