Option B is correct.
ANSWER:
The equation in slope-intercept form, of the line that passes through (0, 6) and has a slope of 4 is y = 4x + 6
SOLUTION:
Given, Point P (0, 6) and slope = 4
We need to find the equation in Slope-intercept form.
The slope intercept form is given as y = mx + c -------- eqn (1)
Where, m is the slope of line
C is intercept made on x-axis by the line.
We have a point and the slope, so first we can find equation using point-slope form and then convert into slope-intercept form.
Now, point-slope form is given as [tex]y-y_{1}=m\left(x-x_{1}\right)[/tex] --- eqn 2
Put [tex]\mathrm{x}_{1}=0 \text { and } \mathrm{y}_{1}=6[/tex] in eqn (2) along with m = 4
[tex]y-y_{2}=m\left(x-x_{1}\right)=y-6=4(x-0)[/tex]
y – 6 = 4x
We got the equation in point slope form, now let’s convert it into slope intercept form.
y – 6 = 4x
y = 4x + 6
Here, slope (m) = 4 and intercept (c) = 6
Hence we can conclude that, equation, in slope-intercept form, of the line that passes through (0, 6) and has a slope of 4 is y = 4x + 6
