Answer: 45000 m/s^2
Explanation:
First, we know:
Bullet's Initial Velocity (Vo) = 0 m/s
Distance Travelled (D) = 1 m
Final Velocity (Vf) = 300 m/s
We need to know the bullets acceleration to reach the final velocity on that distance. Because the bullet stars from rest, his Initial Velocity is equal to zero.
We dont know on how much time it takes for the bullet, but we know the acceleration on the barrel is constant.
We can use the following equation for this
[tex]Vf^{2} = Vo^{2}+2ax[/tex]
Because Vo is zero, the equation simplify, so we have.
[tex]Vf^{2} = 2ax[/tex]
Searching for the accelaration we obtain
[tex]a = \frac{(Vf)^{2} }{2x}[/tex]
Changing values
[tex]a = \frac{(300 m/s)^{2} }{2 * 1m}[/tex]
[tex]a = \frac{(300 m/s)^{2} }{2 * 1m}[/tex]
[tex]a = 45000 m/s^{2}[/tex]
This is the acceleration needed to reach the velocity at the end of the barrel.
