Respuesta :
Answer:
[tex]T_1 = 18 N[/tex]
Explanation:
Net tension force applied on 6 kg block is given as
[tex]T = (m_1 + m_2) a[/tex]
here we will have
[tex]T = 30 N[/tex]
[tex]m_1 = 6 kg[/tex]
[tex]m_2 = 9 kg[/tex]
now we will have
[tex]30 = (6 + 9) a[/tex]
[tex]a = 2 m/s^2[/tex]
Now the tension between two blocks will pull the other end mass i.e. 9 kg
so we will have
[tex]T_1 = m_2 a[/tex]
[tex]T_1 = 9(2)[/tex]
[tex]T_1 = 18 N[/tex]
The tension force is applied over the length of the wire and pulls energy equally on the objects at the ends. The tension force in the rope between the blocks is 18N.
What is a tension force?
The tension force is defined as the force that is transmitted through a rope, string, or wire when pulled by forces acting from opposite sides.
Given that the tension force is 30 N and the masses of the two blocks are 6 kg and 9 kg. The tension force F_t on two blocks is given as,
[tex]F_t = (m_1 +m_2) a[/tex]
Where m1 and m2 are the masses of two blocks and a is the acceleration to pull the blocks.
[tex]30 = (6+9)a[/tex]
[tex]a = 2 \;\rm m/s^2[/tex]
The tension in the rope between the blocks will pull the mass of 9 kg is,
[tex]F = 9 \times 2[/tex]
[tex]F = 18\;\rm N[/tex]
Hence we can conclude that the tension force in the rope between the blocks is 18N.
To know more about the tension force, follow the link given below.
https://brainly.com/question/2287912.
