contestada

There are two coherent microwave sources in the x–y plane. These sources are emitting in phase at a wavelength of ????=1.78 cm. One of the sources, ????1, is located along the y ‑axis at y1, and the second source, ????2, is located at the point x2=3.74 cm, y2=13.4 cm. Assume y1>y2. If the phase difference at the origin between the two sources is ????=152∘, where is the first source located on the y ‑axis?

Respuesta :

Answer:

[tex]y_1 = 14.65 cm[/tex]

Explanation:

As we know the relation between phase difference and path difference

[tex]\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)[/tex]

so we will have

[tex]\Delta \phi = 152^o[/tex]

[tex]\Delta \phi = 0.84 \pi[/tex]

[tex]\frac{2\pi}{1.78 cm}(\Delta x) = 0.84 \pi[/tex]

[tex]\Delta x = 0.75 cm[/tex]

now distance of two sources are

[tex]d_1 = \sqrt{x_2^2 + y_2^2}[/tex]

[tex]d_1 = \sqrt{3.74^2 + 13.4^2}[/tex]

[tex]d_1 = 13.9 cm[/tex]

Now we have

[tex]y_1 - 13.9 = 0.75[/tex]

[tex]y_1 = 14.65 cm[/tex]

Otras preguntas