Answer:
[tex]\dfrac{3}{7},\ \dfrac{2}{3}[/tex]
Step-by-step explanation:
Consider numbers
[tex]x=\dfrac{3}{7} \\ \\y=\dfrac{2}{3}[/tex]
First, check that these numbers are greater than [tex]\dfrac{1}{3}:[/tex]
For x:
[tex]\dfrac{3}{7}=\dfrac{9}{21}\\ \\\dfrac{1}{3}=\dfrac{7}{21}\\ \\\dfrac{9}{21}>\dfrac{7}{21}\Rightarrow x=\dfrac{3}{7}>\dfrac{1}{3}[/tex]
For y:
[tex]\dfrac{2}{3}>\dfrac{1}{3}[/tex]
Now, find the product xy:
[tex]xy=\dfrac{3}{7}\cdot \dfrac{2}{3}=\dfrac{2}{7}=\dfrac{6}{21}<\dfrac{7}{21}=\dfrac{1}{3}[/tex]
