Answer:
17.15 m/s
Explanation:
This is a case of free fall, so we can use the next equation:
[tex]v_{f}^2=v_{i}^2+2gh[/tex]
where
[tex]v_{f}[/tex] is the final velocity
[tex]v_{i}[/tex] is the initial velocity (0 in this case)
[tex]g[/tex] is the acceleration of gravity [tex]9.8m/s^2[/tex]
and [tex]h[/tex] is the height at wich the ballon was pitched.
So we have:
[tex]v_{f}=\sqrt{v_{i}^2+2gh} =\sqrt{0^2+2(9.8m/s^2)(15m)} =\sqrt{294m^2/s^2} =17.15m/s[/tex]
The final velocity, the velocity of the ballon when it hits the ground is 17.15m/s.
