Answer:
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
Explanation:
During the motion of the rock while it is in downward motion we can say
[tex]T - mg cos\theta = ma_c[/tex]
since it is performing circular motion so we will have its acceleration towards its center
[tex]T = mgcos\theta + ma_c[/tex]
[tex]a_c = \frac{v^2}{L}[/tex]
[tex]T = mgcos\theta + \frac{mv^2}{L}[/tex]
So at the lowest point of the path we can say
[tex]T = mg + \frac{mv^2}{L}[/tex]
so correct answer is
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.