For this problem, involving a weighted die, assume that the outcomes 1 through 4 are equally likely, that the outcomes 5 through 6 are equally likely, and that outcome 1 is 3 times as likely as outcome 5.

(1) What probability should be assigned to rolling a 4?


(2) What probability should be assigned to rolling a 6?

Respuesta :

Answer:

a.[tex]\frac{3}{14}[/tex]

b.[tex]\frac{1}{14}[/tex]

Step-by-step explanation:

We are given that a die is rolled

Let x bet the cases in favor of 5.

Number of cases in favor of 6=x

Then according to question

Number of cases in favor of  1=3x

Number of cases in favor of 2=3x

Number of cases in favor of 3=3x

Number of cases in favor of 4=3x

Sum of total cases=[tex]x+x+3x+3x+3x+3x=14x[/tex]

Probability of getting 5 =[tex]\frac{x}{14x}=\frac{1}{14}[/tex]

Probability of getting 1=[tex]\frac{3x}{14x}=\frac{3}{14}[/tex]

1.We have to find probability should be assigned to rolling a 4.

The probability of getting =[tex]\frac{3}{14}[/tex]

2.We have to find the probability of rolling 6.

The probability of getting 6=[tex]\frac{1}{14}[/tex]