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Now assume that two identical cars of mass m drive along a highway. One car approaches a curve of radius 2R at speed v. The second car approaches a curve of radius 6R at a speed of 3v. How does the magnitude F1 of the net force exerted on the first car compare to the magnitude F2 of the net force exerted on the second car

Respuesta :

AMB000

Answer:

F1 is 1/3 of F2

Explanation:

The net force for both cars will be the centrifugal force, because their weight will cancel out with the normal force from the ground.

The equation for the centrifugal force is:

[tex]F=m\frac{v^2}{r}[/tex]

So for both cars we have:

[tex]F_1=m_1\frac{v_1^2}{r_1}=\frac{mv^2}{2R}[/tex]

[tex]F_2=m_2\frac{v_2^2}{r_2}=\frac{m(3v)^2}{6R}=\frac{9mv^2}{6R}=\frac{3mv^2}{2R}[/tex]

So clearly [tex]F_2=3F_1[/tex], which means that the magnitude F1 of the net force exerted on the first car is one third to the magnitude F2 of the net force exerted on the second car.

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