Answer:
Out of four offspring in second generation , 3 are purple color with frequency of 0.23 homozygous purple color flower and 0.25 heterozygous purple color flower
Explanation:
Given ,
Allele for purple color flower is "P"
Allele for white color flower is "p"
Genotype of true breeding purple flower is "PP"
Genotype of true breeding white flower is "pp"
F1 Generation -
PP x pp
Pp, Pp, Pp, Pp
All are purple in color, thus purple color is dominant over white color
F2 generation -
Pp x Pp
PP, Pp, Pp, pp
Given 27 plants are white in color, thus frequency of white recessive flower is
[tex]\frac{27}{27+73} \\\frac{27}{100} \\= 0.27\\p^2 = 0.27\\p = 0.519 = 0.52\\[/tex]
p is the frequency for purple color allele
q is the frequency for white color allele
[tex]q = 1-0.52\\q = 0.48[/tex]
[tex]q^{2}[/tex] represent the frequency of homozygous purple flower
[tex]q^2 = 0.48^2 \\q^2 = 0.23[/tex]
[tex]p^2+ q^2 + 2pq = 1\\2pq = 1 - 0.52 -0.23\\2pq = 0.25[/tex]
In this scenario, Chad determines the genotype of the purple-flowered pea plants in the F2 generation - by the phenotypic ratio which is 1:2:1 where purple-colored flowers are 50% come from the heterozygous condition.
In this type of inheritance pattern when two true-breeding but opposite traits of the same gene are crossed then they produce blending traits as given in this question.
In this case, they always produce blending traits only if both alleles are present together. The purple flower always has an RW allele where W is for white flowers and R represents red flowers.
Learn more about incomplete dominance:
https://brainly.com/question/7294889
