The mass of water = 54 g
Mass of sodium carbonate = 6 g
[tex]Mass of sodium carbonate = \frac{(Volume of water)(percentage mass)}{(100-percentage mass)}[/tex]
In this case;
Percentage mass = 10 %
Total mass of solution = 60 g
Assuming the volume of water = y cm³, the mass of water is y g
Then, the mass of sodium carbonate(solute)= 60-y
Hence;
[tex]60-y = \frac{10y}{(100-10)}[/tex]
[tex]90(60-y) = 10y\\5400-90y =10y\\5400 = 100 y\\y =54[/tex]
Therefore;
The mass of water = 54 g
Mass of sodium carbonate = 6 g