To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed
an empty 3.1-L bulb, then filled it with the gas at 1.00 atm and 28.0 °C and weighed it again.
The difference in mass was 3.5 g. Identify the gas.

Respuesta :

The diatomic gas is Nitrogen.

What is diatomic gas?

Diatomic gases have only two atoms, which can be of the same or distinct chemical elements.

Some diatomic gases are hydrogen, oxygen, bromine, iodine, etc.

Calculation:

Given,

Temperature = 28.0 °C (28 + 273.15 = 301.15 K)

Difference in Mass = 3.5 g

Volume = 3.1 L

Pressure = 1.0 atm.

Step 1: By Boyle's law

[tex]\bold{n = 1\; atm \times\dfrac{3.1 L}{0.0821\; L. atm.} \times 301.15 K}[/tex]

[tex]\bold{n = \dfrac{3.1 L. atm }{24.72 L. atm}= 0.13 mol }[/tex]

Step 2: Now we will calculate the molar mass

[tex]\bold {Molar\; mass = \dfrac{mass}{number \;of \;moles} }[/tex]

[tex]\bold {Molar\; mass = \dfrac{3.5\;g}{0.13\;mol} =26.9 g/mol }[/tex]

As the gas is diatomic, the atomic mass will be half of 26.9 g/mol.

Thus, mass = 13.45 g/mol.

Hence, The diatomic gas which has an atomic mass closer to 13.45 is Nitrogen.

Learn more about diatomic gas, here:

https://brainly.com/question/2841701

The gas is diatomic so, atomic mass will be half of 26.9 g/mol.

26.9 g/mol / 2 = 13.45 g/mol

The diatomic gas which has an atomic mass closer to 13.45 is Nitrogen.