Suppose a smokejumper jumps from an altitude of 13,000 feet. If he's 65 percent of his way down, how far is he from the ground?

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mikeandfalen mikeandfalen · Answer 1 · 2019-10-08T06:57:35+02:00

Answer:

4550 feet

Step-by-step explanation:

13000 x .65% = 8450 feet he has descended

13000 - 8450 = 4550 feet from the ground

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crose47 crose47 · Answer 2 · 2019-10-08T07:14:00+02:00

Answer: 4550 feet to the ground

Step-by-step explanation: 13000 ft x 65% =

8450 feet

13000 ft

- 8450 ft

= 4550 ft to the ground

Answer Link