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∠A=10x+24 ∘ space, start color blueD, angle, A, equals, 10, x, plus, 24, degree, end color blueD \qquad \green{\angle B=6x + 72^\circ} ∠B=6x+72 ∘ space, start color green, angle, B, equals, 6, x, plus, 72, degree, end color green

Respuesta :

calculista

Answer:

m∠B=144°

Step-by-step explanation:

see the attached figure to better understand the problem

we have

Two parallel lines cut by a transversal.

so

m∠A=m∠B -----> by alternate interior angles

substitute the given values and solve for x

[tex](10x+24)\°=(6x+72)\°[/tex]

[tex]10x-6x=72-24[/tex]

[tex]4x=48[/tex]

[tex]x=12[/tex]

Find the measure of m∠B

m∠B=(6x+72)°

substitute the value of x

m∠B=(6(12)+72)°=144°

Ver imagen calculista

Answer:

Vertical Angles

Step-by-step explanation:

This is correct on Khan Academy!