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A student observes 5,000 RFUs in a 200μl aliquot from a G3-500 ml culture. How many total RFUs will be present in a G3-15ml sample? During rGFP purification in lab#4, assume they recover 80% of the fluorescing protein. What would be the maximum total number of RFUs that they collected in the purification procedure? Show your calculations for full credit.

Respuesta :

Answer:

The maximum no. of RFUs collected in the purification procedure [tex]= 3.05 \times 10^5[/tex] RFUs

Explanation:

No. of RFUs in a 200 ul (0.2ml) aliquot = 5000 RFUs

So, No. of RFUs in G3-500 ml culture [tex]= 5000 \times \frac{500 ml}{0.2 ml}[/tex] RFUs

                                                               [tex]= 5000 \times 2500[/tex] RFUs  

                                                                [tex]= 1.25 \times 10^7[/tex] RFUs

Similarly, No. of RFUs in a G3-15ml sample [tex]= 5000 \times \frac{15 ml}{0.2 ml}[/tex] RFUs

                                                                          [tex]= 5000 \times 75[/tex] RFUs

                                                                          [tex]= 3.75 \times 10^5[/tex] RFUs

The maximum no. of RFUs collected in the purification procedure

[tex]= 3.75 \times 10^5 \times 80[/tex]% RFUs

[tex]= 3.75 \times 10^5 \times 0.80[/tex] RFUs

[tex]= 3.05 \times 10^5[/tex] RFUs

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