Answer:
(a) P(green candy or blue candy)=14%
These outcomes are mutually exclusive. Choosing a green and blue M&M is not possible.
(b) P(yellow candy or red candy)= 40% These outcomes are mutually exclusive. Choosing a yellow and red M&M is not possible.
(c) P(not purple candy)=77%
Step-by-step explanation:
To get the probability equally likely of having a candy we use the following formula
P=# of possibilities that meet the condition / #of equally likely possibilities.
In this case, we are consider 100 candies as the number of equally likely possibilities.
P(green candy or blue candy)
green candy= 7 candies over 100 ( 7 %)
blue candy= 7 candies over 100 ( 7 %)
P(green candy or blue candy)= 7+7 / 100= 14/100=14%
Are these outcomes mutually exclusive? Yes. Choosing a green and blue M&M is not possible. Both can't occur at the same time.
(b) P(yellow candy or red candy)
yellow candy= 21 candies over 100 ( 21 %)
red candy= 19 candies over 100 ( 19 %)
P(yellow candy or red candy)= 21+19 / 100= 40/100=40%
Are these outcomes mutually exclusive? Yes. Choosing a green and blue M&M is not possible.
(c) P(not purple candy)= to get this probability we have to consider the others possibilities, we can get Yellow, Red, Orange, Green, Blue or Brown,
that means 21+ 19+ 10+ 7+ 7+ 13=77
P(not purple candy)= 77/100= 77%