Respuesta :
Answer:
The percentage difference between two countries is 12.5%
Step by Step Explanation:
Given:
Average consumption of electricity in Blacksburg city=900[tex]\frac{k w h}{m o n t h}[/tex]
Average consumption of electricity in Springfield=1020[tex]\frac{k w h}{m o n t h}[/tex]
To find:
Percentage difference between the average consumption in two towns
Solution:
According to the formula, percentage difference is calculated as
[tex]\text { Percentage difference }=\frac{\text { Value of larger town-Value of smaller town }}{\text { sum value of two town/2 }} \times 100[/tex]
Value of larger town=Average consumption of electricity in Springfield
=1020[tex]\frac{k w h}{m o n t h}[/tex]
Value of smaller town= Average consumption of electricity in Blacksburg
=900[tex]\frac{k w h}{m o n t h}[/tex]
Sum value of two towns=1020+900=1920
Substitute these values in the above equation we get
[tex]\text { Percentage difference }=\frac{1020-900}{1920 / 2} \times 100[/tex] [tex]=\frac{120}{960} \times 100[/tex]
[tex]=0.125 \times 100[/tex]
[tex]=12.5 \%[/tex]
Result:
Thus the percentage difference between the average consumption of electricity between two towns =12.5%
