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At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 760 m/s2 and the vertical or y component of its acceleration is 770 m/s2. The ball's mass is 0.40 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

Respuesta :

Answer:

Magnitude of net force will be 432.758 N  

Explanation:

We have given x component of acceleration [tex]a_x=760m/sec^2[/tex]

And vertical component of acceleration  [tex]a_y=770m/sec^2[/tex]

Mass of the ball m = 0.40 kg

So net acceleration [tex]a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2[/tex]

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

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