Answer:
Height of the stone face = 66.29 feet
Step-by-step explanation:
Refer the given figure, here we need to find height of the stone face,
Height of the stone face = CD
CD = AD - AC
In ΔABC we have
[tex]tan31=\frac{AC}{AB}\\\\tan31=\frac{AC}{900}\\\\AC=540.77feet[/tex]
In ΔABD we have
[tex]tan34=\frac{AD}{AB}\\\\tan34=\frac{AD}{900}\\\\AD=607.06feet[/tex]
CD = AD - AC = 607.06 - 540.77 = 66.29 feet
Height of the stone face = CD = 66.29 feet