Answer:
x = 0 , F= 0
Explanation:
To find the elastic force of a spring we use Hooke's law
F = - k x
Done k is the Hooke constant and x is the displacement of the spring from its equilibrium point.
They give us the equation of motion of the harmonic oscillator
x = 0.34 sin (π t)
The form of the theoretical equation is
x = A cos (wt + Φ)
To transform the expression the phase must be 90º and the angular velocity is
w² = k / m
x = A cos (wt + 90) = A [cos wt sint 90 + cos 90 sint wt]
Cos 90 = 0
x = A sin( wt)
Now let's calculate the offset for 1 s
x = 0.34 sin (π 1)
x = 0.34 (0)
x = 0
For this displacement the force is zero
