Answer: 0.23
Step-by-step explanation:
Given : F is the event "works in the finishing department;"
and A is the event "is absent excessively."
Given : 10% of all plant employees work in the finishing department; 20% of all plant employees are absent excessively; and 7% of all plant employees work in the finishing department and are absent excessively.
i.e. P(A)= 0.20 ; P(F)=0.10 ; P(A ∩ F) = 0.07
We know that [tex]P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)[/tex]
Then,
[tex]P(A\cup F)=P(A)+P(F)-P(A\cap F)\\\\\Rightarrow\ P(A\cup F)=0.20+0.10-0.07=0.23[/tex]
Hence, the required answer is [tex]P(A\cup F)=0.23[/tex]