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An exponential relationship exists between the explanatory variable and the response variable in a set of data. The common logarithm of each value of the response variable is taken, and the least-squares regression line has an equation of log(yˆ)=7.3−1.5xlog⁡(y^)=7.3−1.5x. Which value is closest to the predicted value of the response variable for x=4.8x=4.8 ?

Respuesta :

lucic

The value closest to predicted value is 1.258

Step-by-step explanation:

The question requires you to substitute the value of x=4.8 in the least-squares regression line

The equation given is log (y)= 7.3 - 1.5x

Replacing x with real value, 4.8 you will have;

log(y) = 7.3 - 1.5(4.8)

log(y)= 7.3-7.2

log(y)=0.1

y=10^0.1

[tex]y=10^{0.1}[/tex]

y=1.258

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  • Least square regression line: https://brainly.com/question/13353498

Keywords: exponential relationship,least-squares regression line,logarithm

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Answer:

Answer D

Step-by-step explanation:

Substituting x=4.8 into the equation gives log(yˆ)=7.3−1.5(4.8) or log(yˆ)=0.1. To solve for yˆ, raise 10 to the power of 0.1 to get 1.26.

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