Answer:
116 N
Explanation:
Missing question: (found on google)
"What is the force of the pitcher's hand on the 0.145 kg ball during this acceleration phase?
Express your answer with the appropriate units."
Solution:
First of all, we need to calculate the acceleration of the ball, given by
[tex]a=\frac{v-u}{\Delta t}[/tex]
where
v = 40 m/s is the final velocity
u = 0 is the initial velocity
[tex]\Delta t = 50 ms = 0.050 s[/tex] is the duration of the acceleration phase
Substituting,
[tex]a=\frac{40-0}{0.05}=800 m/s^2[/tex]
Now we can find the force exerted on the ball by using Newton's second law:
[tex]F=ma[/tex]
where
m = 0.145 kg is the mass of the ball
a is the acceleration
Substituting,
[tex]F=(0.145)(800)=116 N[/tex]
