Respuesta :
Answer
given,
A bag consist of 29 tulip bulbs
a) P(both bulb are red ) =
=[tex]P(first\ red\ bulb) \times P(second\ red\ bulb)[/tex]
= [tex]\dfrac{10}{29} \times \dfrac{9}{28})[/tex]
= 0.111
P(both bulb are red ) = 0.111
b) P(first bulb is red and second yellow ) =
= [tex]P(first\ red\ bulb) \times P(second\ yellow\ bulb)[/tex]
= [tex]\dfrac{10}{29} \times \dfrac{12}{28})[/tex]
= 0.148
P(first bulb is red and second yellow ) = 0.148
c) P(first bulb is yellow and second red ) =
=[tex]P(first\ yellow\ bulb) \times P(second\ red\ bulb)[/tex]
=[tex]\dfrac{12}{29} \times \dfrac{10}{28})[/tex]
=0.148
P(first bulb is yellow and second red ) = 0.148
d) P(one bulb is red and the other yellow) =
= P(first bulb is yellow and second red ) + P(first bulb is red and second yellow )
= 0.148 + 0.148
= 0.296
P(one bulb is red and the other yellow) = 0.296
