Answer:
(A) Time period T = 6.28 SEC
(B) At highest point fore is - 575.83 N
(B) At lowest point force is 1050.97 N
Explanation:
We have given that mass m = 83 kg
Radius r = 13 m
Speed v = 6.10 m/sec
(A) Time period of the motion is given by [tex]T=\frac{2\pi r}{v}=\frac{2\times 3.14\times 13}{6.10}=6.28sec[/tex]
(b) Net force is given by [tex]F_{NET}=\frac{mv^2}{r}=\frac{83\times 6.10^2}{13}=237.571N[/tex]
Force due to gravity [tex]F_{gravity}=mg=83\times 9.8=813.4N[/tex]
At highest point [tex]F_{NORMAL}=F_{NET}-F_{GRAVITY}=237.57-813.4=-575.83[/tex]
(B) At lowest point [tex]F_{NORMAL}=F_{NET}+F_{GRAVITY}=237.57+813.4=1050.97N[/tex]
