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Chromium(III) sulfate is a transition metal compound containing the metal chromium and the polyatomic ion sulfate. The oxidation state of chromium in this compound is , and the chemical formula of the compound is ( ) .

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Answer:

The answer to your question is: Oxidation number is III,

formula     Cr₂(SO₄)₃

Explanation:

Data

Chromium (III) sulfate

Oxidation state of Cr = ?

Chemical formula

Process

The oxidation number of Chromium is given in roman numerals, then the oxidation number is III.

Chemical formula              Cr₂(SO₄)₃

Answer:

Chromium oxidation state is 3.

Formula Cr2(SO4)3

Explanation:

At the beggining of the exercise, the chromium sulfate, says the oxidation state of chromium in romans numbers (III). This number usually indicates the oxidation state of any element. In this case the Chromium shouldhave an oxidation state of 3.

Now, in order to form the chromium(III) sulfate we need to make a reaction between the sulfuric acid and chromium. In this case:

Cr + H2SO4 ---------> Cr2(SO4)3 + H2O

That's why the chromium sulfate has that formula.

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