Answer:
Acceleration of the bullet will be 1778835.6 [tex]m/sec^2[/tex]
Explanation:
We have given length of the barrel refile s= 0.855 m
When the bullet leaves the muzzle its velocity is 553 m/sec
So final velocity v = 553 m/sec
Initial velocity will be 0 that is u = 0 m/sec
According to third equation of motion [tex]v^2=u^2+2as[/tex]
[tex]553^2=0^2+2\times a\times 0.855[/tex]
[tex]a=178835.6m/sec^2[/tex]