Answer:
No, it is independent
Explanation:
As we know that car is moving horizontally
so the vertical component of the speed is zero initially
so in order to hit the ground we know that
[tex]\Delta y = v_y t + \frac{1}{2}at^2[/tex]
so here we know that
[tex]h = 0 + \frac{1}{2}gt^2[/tex]
on solving above equation for time
[tex]t = \sqrt{\frac{2h}{g}}[/tex]
so we will say that it will not depends on the initial horizontal speed