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A quarterback threw a football at 24 m/s at a 45° angle. If it took the ball 3 seconds to reach the top of its path.
how long was it in the air? Assume the ball is caught at the same height that it left the quarterback's hand.

Respuesta :

Answer:

6 seconds

Explanation:

If it took the ball 3 seconds to reach the maximum height, then it also took 3 seconds to return to its original height.  So it was in the air for a total of 6 seconds.

The time for the ball to be in the air will be 6 seconds.

What is the period?

The period is found as the ratio of the displacement and the velocity. Its unit is the second and is denoted by t.

The value of time needed to complete the upward and the downward motion is the total period. T is the time at which the ball first hits the ground.

The given data in the problem is;

The time required to move upwards is,t₁ = 3 sec

The time required to move downwards is,t₂ = 3 sec

The total period is the sum of the time required to move upwards and the time required to move downwards.

T =t₁+t₂

T =3 +3 sec

T=6sec

Hence the time for the ball to be in the air will be 6 seconds.

To learn more about the period, refer to the link;

https://brainly.com/question/569003

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