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Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 46-N pushing force Modifying Above P With right-arrow is horizontal and is applied to the 24-kg box, which in turn pushes against the 62-kg box. Find the magnitude of the force Modifying Above F With right-arrow that the 24-kg box applies to the 62-kg box.

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debrubs97

Answer:

33.16N

Step-by-step explanation:

The 46 N force is causing both boxes to accelerate. To determine the acceleration, we are going to use Newton's laws of motion

F=m*a --> a=F/m

You know that the Force is 46 and the mass is the sum of both boxes (cause you are moving the two of them)

a =46 ÷ (24 + 62) = 46 ÷ 86  

This is approximately 0.535 m/s. This is the acceleration of both boxes. To determine the force that the 24-kg box applies to the 62-kg box, you use the newton's law of motion. But now you know the acceleration and the mass

F=m*a=62*0.535m/s=33.16 N

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