Answer:
Explanation:
First calculate
(a)
R₁=[tex]\frac{L}{k}[/tex]
R₁= 0.01/16.6
=6.024*10⁻⁴ m² . K/W
R₁=R₂=6.024*10⁻⁴ m² . K/W
The contact thermal resistance of AISI 304 stainless steel
[tex]R_{contact}[/tex]= 15*10⁻⁴ m² . K/W
R=R₁+R₂+[tex]R_{contact}[/tex]
R=6.024*10⁻⁴+15*10⁻⁴ +6.024*10⁻⁴
R=27.048 *10⁻⁴ m² . K/W
Calculate the rate of heat transfer
q=ΔT/R
=110/(27.048 *10⁻⁴)
q= 40668.44 W/m²
(b)
Calculate the difference of temperature across the plate
[tex]\frac{ΔT_{contact} }{ΔT} =\frac{R_{contact} }{R}[/tex]
ΔT=110*[tex]\frac{15*10^{-4} }{27.048*10^{-4} }[/tex]
ΔT=61.002 K
