Answer:295.71 m
Explanation:
Given
Plane is flying 90 m above
Speed of plane=69 m/s
Let x be the distance from the target pilot release the canister
time taken to travel 90 m is
[tex]h=ut+\frac{at^2}{2}[/tex]
[tex]90=0+\frac{gt^2}{2}[/tex]
[tex]t^2=18.367[/tex]
t=4.28 s
x=ut
[tex]x=69\times 4.28=295.71 m[/tex]