Answer:
The final rotation is 2.449 times the initial rotation
Explanation:
Centripetal acceleration and rotation speed of particle is related as
a=rω²
where ω is angular speed and r radius of circle
Rearranging equation
ω=[tex]\sqrt{\frac{a}{r} }[/tex]
The initial acceleration is given by
a₁ =100g
The final acceleration of particle is
a₂ = 6 (100g)
=600g
The final and initial rotation speed are related as
[tex]\frac{w1}{w2} =\sqrt{\frac{a2}{a1 }[/tex]
ω2=[tex]\sqrt{\frac{600g}{100g} } *w1[/tex]
ω2=2.449ω1