A. The initial velocity of the wrench is + 6 m/s
B. The velocity of the wrench at two seconds is 13.6 m/s downward
C. The wrench is at 7.6 meters from the release point after 2 seconds
D. The wrench is 19.6 meters below the helicopter after 2 seconds
Explanation:
A wrench falls from a helicopter that is rising steadily at +6.0 m/s
1. The speed of the helicopter is 6 m/s
2. The initial speed of the wrench is the same speed of the helicopter
A.
The initial velocity of the wrench is + 6 m/s
B.
The velocity after 2 seconds can be get by using the rule:
→ v = u + gt
where v is the final velocity u is the initial velocity, g is the
acceleration of gravity and t is the time
→ u = 6 m/s , t = 2 seconds , g = -9.8 m/s²
→ v = 6 - 9.8(2) = -13.6 m/s
Negative sign means the direction of velocity is downward
The velocity of the wrench at two seconds is 13.6 m/s downward
C.
We can find the distance that the wrench releases by using the rule:
→ s = ut + [tex]\frac{1}{2}[/tex] g t²
where s is the distance
→ u = 6 m/s , g = -9.8 m/s² , t = 2
→ s = 6(2) - [tex]\frac{1}{2}[/tex] (9.8)(2)²
→ s = 12 - 19.6 = -7.6 meters
We will ignore the negative sign because distance is a scalar quantity
The wrench is at 7.6 meters from the release point after 2 seconds
D.
The distance covered by the helicopter is the speed of the helicopter
Multiplied by the time
→ The speed of the helicopter is 6 m/s
→ The time is 2 seconds
→ The distance covered by the helicopter = 6 × 2 = 12 meters
→ The distance covered by the wrench is 7.6 meters
The total distance is the sum of the distance covered by the
helicopter and the distance covered by the wrench
→ The total distance = 7.6 + 12 = 19.6 meters
The wrench is 19.6 meters below the helicopter after 2 seconds
Learn more:
You can learn more about the free fall motion in brainly.com/question/5531630
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