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A 20 N horizontal force F pushes a block weighing 3.0 N against a vertical wall. The coefficient of static friction between the wall and the block is 0.60, and the coefficient of kinetic friction is 0.40. Assume that the block is not moving initially.
In unit-vector notation, what is the force exerted on the block by the wall?
(___)N ihad + (____)N jhad

Respuesta :

Answer:[tex]F=20\hat{i}-3\hat{j}[/tex]

Explanation:

Given

Force=20 N

weight of Block=3 N

coefficient of static friction[tex](\mu_ s)[/tex]=0.60

coefficient of kinetic friction[tex](\mu_ k)[/tex]=0.40

Forces Acting on the block is

F=20 N,Weight , friction Force , Normal Reaction

Now Force acting on the wall is Normal reaction and friction

Normal reaction will act in  + x direction while friction will act in - y direction

N=20 N

f=mg=3 N

[tex]F=20\hat{i}-3\hat{j}[/tex]

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