Answer:
a) 0,014 min⁻¹
b) 1452 seconds.
c) 0,02156 M
d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction
Explanation:
a) For a first order reaction the half-life is:
[tex]t_{1/2} = \frac{ln(2)}{k}[/tex] (1) As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹
b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.
As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds
c) In the same way, 11072 years are 4 half-life for this reaction, thus:
0,345M/2⁴ = 0,02156 M
d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.
By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction
I hope it helps!
