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What are the solution(s) to the quadratic equation 40 − x2 = 0?

x = ±2Plus or minus 2 StartRoot 10 EndRoot
x = ±4Plus or minus 4 StartRoot 10 EndRoot
x = ±2Plus or minus 2 StartRoot 5 EndRoot
x = ±4Plus or minus 4 StartRoot 5 EndRoot

Respuesta :

mberisso

Answer:

[tex]x=+/- 2\sqrt{10}[/tex]

Step-by-step explanation:

This equation can be solved directly by isolating the quadratic term in x on one side of the equation (this is because there is no linear term in x n he equation) as follows:

[tex]40-x^2=0\\40=0+x^2\\40=x^2\\x^2=40\\\sqrt{x^2} =+/- \sqrt{40} \\x=+/-\sqrt{4*10} =+/-\sqrt{4} *\sqrt{10} =+/- 2\sqrt{10} \\x=+/- 2\sqrt{10}[/tex]

wilson15car

Answer: The answer is A.x = ±2Plus or minus 2 StartRoot 10 EndRoot

Step-by-step explanation:

40-x^2=0

x^2=40

x=square root of 40

factor 40

x=square root of 2*2*10

x = 2 StartRoot 10 EndRoot

since its squared

it means  that it can either be positive or negative

which is why its A.x = ±2Plus or minus 2 StartRoot 10 EndRoot

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